O O is the center of the circum circle of a triangle ABC. <A=40^ ,<B=80^ , <C=60^ BC = 6.4 cm a) What is the diameter of the circle? b) What is the length of the other two sides?
Answers
Answered by
0
Answer:
Given ∠A=40
o
,∠B=80
o
∠=60
o
,BC=6.4cm
a. Diameter (d)=
sinA
BC
=
sin40
64
=
0.64
6.4
=10cm
b. Side AC=d×sinB=10×sin8
=10×0.98=9.8cm.
Side AB=d×sinC=10×sin60
=10×0.87=8.7cm.
Similar questions