Question

o p q is a quadrant of a circle with Centre O and radius 7cm an isosceles triangle O A B is cut of the quadrant such that BQ = AP equals to 3 cm calculate the area of the shaded region

Answer 1

Answer:

Step-by-step explanation:

Area of Shaded Region APQB = Area of quadrant OPQ - Area of Triangle OAB

Area of Quadrant = 1/4 * $\pi r^{2}$

                              = 1/4 * 3.14* $7^{2}$

                              = 38.465 $cm^{2}$.

Area of Triangle OAB = OB*OA/2

                                    = 4*4/2

                                     = 8 $cm^{2}$.

Area of Shaded Region = Area of quadrant OPQ - Area of Triangle OAB

                                  = 38.465 - 8

                                   = 30.465  $cm^{2}$.