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The locus of the foot of perpendicular drawn from the centre of the ellipse x²+ 3y² = 6 on any tangent to it is ¿?¿
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☣️☣️☣️☣️ HEYA BUDDY ☣️☣️☣️☣️
⭐️⭐️⭐️ ANSWER ⭐️⭐️⭐️
⏩⏩ let us take the foot of perpendicular as (a,b)
equation of tangent
y = mx ± √6m² + 2
(m = -a/b)
√(6a²/b² + 2) = (a² + b²)/b
6a² + 2b² = (a² + b²)²
✨ hOpE iT heLpS ❗️❗️
⭐️⭐️⭐️ ANSWER ⭐️⭐️⭐️
⏩⏩ let us take the foot of perpendicular as (a,b)
equation of tangent
y = mx ± √6m² + 2
(m = -a/b)
√(6a²/b² + 2) = (a² + b²)/b
6a² + 2b² = (a² + b²)²
✨ hOpE iT heLpS ❗️❗️
shinevv:
@riddhi140
np ^^
hehe thnks sir ❗️
haha
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