O={x/x belongs to I and x square <10}
Answers
Answer:
O = {-3, -2, -1, 0, 1, 2, 3}
Step-by-step explanation:
We know that, squares are always positive even though the number whose square is taken is negative.
- According to the condition,
Let us take the square numbers and then check the numbers of elements
0 = 0²
1 = 1² or (-1)²
4 = 2² or (-2)²
9 = 3² or (-3)²
As the next square number is 16 we must not let consider that number because the condition given is x² < 10 but 16> 10
So, the elements of the set are -3, -2, -1, 0, 1, 2 and 3
❖ Extra information :
⟡ What is a Set - builder form?
=> Set builder notation is a mathematical notation of describing a set by listing its elements or demonstrating its properties that its members must satisfy.
It is represented by => If A is any set, then
A = {x | x = condition for elements in the set}
⟡ What is a Roster form?
=> All the elements of a set are listed, the elements are being separated by commas and are enclosed within braces { }. In other words, elements of the set are just noted down in the curly brackets separated by commas.
It is represented by => If B is any set and a, b, c and d are the elements, then
B = {a, b, c, d}
❖ Learn More:
brainly.in/question/43463843
Hope it helps!