Question

o2-2 will have bond order _than O2 and bond order_ to h2
​

Answer 1

Explanation:

o2-2 has bond order less than o2 because in o2 double bond there while in o2-2 there will be single bond and so it's bond order will be same as H2 as it also has single bond

please mark answer brainliest if u like

Answer 2

Answer:

Bond order of [O₂]²⁻ is smaller than that of O₂ but equal to the bond order of H₂.

Explanation:

To find the bond order,

               Bond order  $=\frac{1}{2}(Antibonding-Bonding)$

Antibonding means electrons in Antibonding and same goes for bonding.

For [O₂]²⁻ : σ1s² σ*1s² σ2s² σ*2s² σ2pz² π2pₓ² π2py² π*2p²ₓ  π*2p²y  

∴      Bond order  [O₂]²⁻ = $\frac{1}{2}(10-8)=1$

For O₂ :  σ1s² σ*1s² σ2s² σ*2s² σ2pz² π2pₓ² π2py² π*2p¹ₓ  π*2p¹y

∴    Bond order of O₂ $=\frac{1}{2}(10-6)=2$

For H₂ : σ1s² σ*1s¹

∴    Bond order of H₂ $=\frac{1}{2}(2-0)=1$

Therefore [O₂]²⁻ will have bond order smaller than O₂ and bond order equal to H₂.