OA and OB are mutually perpendicular radii of a circle find the area of minor segment if the perimeter of corresponding minor sector is 20 cm
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OA and OB are mutually perpendicular radii
⇒ OA and OB forms a right angle,
⇒ ΔOAB is a quarter of the circle
Find r:
Perimeter of the sector = 1/4 (2πr) + 2r
Given Perimeter of the sector = 20 cm
1/4 (2πr) + 2r = 20 cm
2πr + 8r = 80
r ( 2π + 8) = 80
r = 5.6 cm
Find the area of the sector:
Area of the sector = 1/4 (πr²)
Area of the sector = 1/4 π(5.6)² = 24. 64 cm²
Find the area of the triangle:
Area of the triangle = 1/2 x base x height
Area of the triangle = 1/2 x 5.6 x 5.6 = 15.68 cm²
Find the area of the minor segment:
Area of the segment = Area of the sector - Area of the triangle
Area of the segment = 24. 64 - 15.68 = 8.96 cm²
Answer: Area of the segment = 8.96 cm²
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