OA and OB are two mutually perpendicular radii of a circle of radius 10.5 CM. D belongs to OB and OD=6 CM. find the area of the coloured region
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Hope it helps.
By the figure , it is clear that we first need to find the area of quadrant.
Secondly, the area not shaded in the quadrant is forming a right angled triangle.
To find out the shaded area we have to subtract bigger area and smaller area.
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Step-by-step explanation:
Given :
Radius of sector OACB(r) = 10.5 =105/10= 21/5 cm
θ = 90°
For ∆ AOD , OA = 10.5 cm , OD = 6cm
Area of blue Coloured region = Area of sector OACB - Area of ∆AOD
Area of blue Coloured region = (πr²θ)/360° - ½ OA× OD
= (22/7 × 21/2 × 21/2 × 90°/360°) - ½ × 21/2 × 6
=( 11 × 3 × 21)/8 - 63/2
= 693/8 - 31.5
= 86.625 - 31.5
Area of blue colour region = 55.125 cm²
Hence, the Area of blue Coloured region = 55.125 cm²
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