OAB IS an equilateral triangle .If O is the centre of circle find the measure of angle ACB
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33
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Angle aob, oba, bao =60degree ( equilateral triangle)
And angle abc= 90° ( right angle)
So a angle acb = 180°- (90+60)
=180-150=30°
Angle aob, oba, bao =60degree ( equilateral triangle)
And angle abc= 90° ( right angle)
So a angle acb = 180°- (90+60)
=180-150=30°
Answered by
30
By theorem
=>The angle subtended by an arc at the center is doubled the angle subtended by it at any point on the remaining part of circle.
& angle of equilateral triangle is 60°.
So, following this
angleAOB=2angleACB
60°/2=angleACB
30°=angle ACB.
=>The angle subtended by an arc at the center is doubled the angle subtended by it at any point on the remaining part of circle.
& angle of equilateral triangle is 60°.
So, following this
angleAOB=2angleACB
60°/2=angleACB
30°=angle ACB.
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