Question

Object accelerates from rest to a velocity of 30m/s in 10s then find the distance covered by object in next 10s. (a) 450m (b) 300m (c) 150m ( d ) 600m Answer fast!!!!!

Answer 1

Answer:

(C) 150 metres

Explanation:

Given :

• Initial velocity = u = 0 m/s

• Final velocity = v = 30 m/s

• Time taken = t = 10 seconds

To find :

• Distance travelled during this period

Using the first equation of motion :

V=u+at

30=0+a×10

30=10a

a=30/10

a = 3 m/s²

Now using the third equation of motion :

V²-u²=2as

30²-0²=2×3×s

900=6s

s = 900/6

s = 150 metres

Hence option c is correct