object is released from height of hundred metre find required time to reach at the ground and final speed before leveling the ground
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hii and the answer is not will take time of 0.02s
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h=ut+1/2gt^2
h=1/2gt^2
100=1/2×10×t^2
t=√20
=2√5
v=u+gt
v=0+10×2√5
=20√5
h=1/2gt^2
100=1/2×10×t^2
t=√20
=2√5
v=u+gt
v=0+10×2√5
=20√5
vivekmaster1abp9g2k3:
how
since height is given so we can find the time... and as body is dropped so initial velocity is zero
solve it according to 9th class
s=ut+1/2at^2. As it is a free fall a=g, u=0. distance travelled (h)= 0×t + 1/2 gt^2. 100=1/2×10×t^2. t^2=20. t=√20 =2√5. velocity when it will reach the ground can be calculated as v=u+at. v=0+gt=10×2√5=20√5
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