Question

object of height cm is placed at 10cm in front of a convex lens of focal length 15cm find height nature and position of image?​

Answer 1

Answer:

a. Mirror formul: 1v+1u=1f

Here, u=−10cm,f=−15cm

∴1v=110−115=15−10(15)(10)=130

The positive sign indicates that the image is virtual and erect and it is formed behind the mirror.

Alternatively, we can apply Newton's formul.

Here, x0=u−f=−10−(−15)=5cm

x1=f2x0=(15)25=45cm

Since xi=v−f, therefore

v=xi+f=45−15=30cm

The magnification,

m=−vu=hih0

hi=h0(−vu)=1(−30−10)=3cm

HOPE THIS HELPS!!

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