Question

object takes 5 s to reach the ground from a height of 5 m on a planet.what is the value of g on the planet

PLEASE ANSWER CORRECTLY SO THAT I CAN UNDERSTAND IN A BEST WAY AND ALSO PLEASE EXPLAIN IT

THANK YOU........

Answer 1

Explanation:

this is the answer bro

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Answer 2

Explanation:

$s = ut + \frac{1}{2} a {t}^{2} \\ let \: us \: assume \: that \: it \: is \: just \: released \\ therefore \: u = 0 \\ s = \frac{1}{2} a {t}^{2} \\ 5 = \frac{1}{2} g {5}^{2} \\ \frac{5}{25} \times 2 = g \\ 0.4 = g$

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