CBSE BOARD XII, asked by moresonu706, 1 month ago

Observation Table: 1 Initial temperature of 0.5 M HCI 26.9C 5 25°C 2 Initial temperature of 0.5 M NaOH 1 100 g 3 Mass of solution = Total volume of solution m 25.0 4 Average temperature of both solutions (HCI + NaOH) 25 (1) 25 (1) 2 5 Pinal temperature of mixture t 27.80 6 Rise in temperature 250 At-SC (0)-25 (1) 4.184 J/g °C 7 Specific heat capacity of water S Calculation:

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Answered by vinaydeepak78

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Answer:

what is your question sorry I not understand

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