Question

observations.
10. An object 5 cm in length is held 25 cm away from a converging lens of focal
10 cm. Draw the ray diagram and find the position, size and the nature
image formed.​

Answer 1

Hope this helps

Object beyond 2F1

Image between F2 and 2F2

Answer 2

Given :

• An object 5 cm in length is held 25 cm away from a converging lens of focal 10 cm.

To Find:

• Position, size and the nature image formed.

Solution:

$\begin{lgathered}\\\end{lgathered}$

✞USING FORMULA:

$\:\:\: \: \: \: \: \: \: \red{ \underline{ \boxed{ \bf{ Mirror \: formula=\dfrac{1}{f} = \dfrac{1}{v} - \dfrac{1}{u} }}}} \: \red{\star }$

$: \implies{ \sf{\dfrac{1}{v} = \dfrac{1}{10} - \dfrac{1}{15} }} \\ \\ : \implies{ \sf{\dfrac{1}{v} = \dfrac{3}{50} }} \\ \\ : \implies{ \sf \: v = \dfrac{50}{3} }$

Hence, The image is real and inverted

✞ MAGNIFICATION:

$\: \: \: \: \: \: \: \:\: \: \: \: \red{ \underline {\boxed{ \bf{Magnification = \dfrac{ h_{1} }{ h_{o} } = \dfrac{v}{u} }}}} \: \red{ \star}$

$:\implies \sf \dfrac{ h_{1} }{5} = \dfrac{ - 16.7}{25}\\ \\ :\implies \sf h_{1} = \dfrac{ - 10}{3} cm$

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