Observe the following balanced chemical equation and answer the given questions.
C3H8(g) + 5O2(g)
4H2O(l)
1)How many molecules of oxygen are involved in this chemical reaction?
ii) How many moles of propane are required to get 20 moles of water?
Answers
Answered by
2
Answer:
Answer
Correct option is
D
72.0g
The molar masses of propane and water are 44 g/mol and 18 g/mol respectively.
44.0 grams of propane corresponds to 1 mole of propane.
According to the balance chemical equation, C
3
H
8
(g)+5O
2
(g)→3CO
2
(g)+4H
2
O(l),
1 mole of propane gives 4 moles of water.
Thus, the combustion of 44.0 g (1 mole) of propane will give 4 moles of water.
Mass of water obtained =4×18=72.0 g.
Hence, option D is correct.
hope it helps you
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