Question

observe the following diagram and write the answers 1.identify the element 2. how many electrons there ? 3. name the second cell of the atom 4. how many electrons there in this shell​

Answer 1

Answer:

it is sodium

Explanation:

please mark me as brainliest

Answer 2

The Main Answer is: 1.) Sodium

                                    2.) 11 electrons

                                    3.) L shell

                                    4.) 8 electrons

Given: A Lewis dot structure of an atom

To Find: 1. Identify the element.

              2. How many electrons are there?

              3. Name the second cell of the atom.

              4. How many electrons are there in this shell​?

Solution:

1.)

• The given structure of the atom has been labeled as "Na".
• This is the chemical formula for Sodium metal.
• Also, there are a total of 11 electrons present in the atom.
• As the no. of electrons = no. of protons = 11
• The atomic no. (no. of protons) for the given atom = 11
• And the element with atomic no. 11 is Sodium.

2.)

• As mentioned above, on counting, one can find that the number of electrons in the given atom = 11

3.)

• In general, the shells of any atom are labeled as K, L, M, N, and so on; where K = 1st shell, L = 2nd shell, and so forth.
• Therefore, here, the second shell of the atom is the L shell.

4.)

• In the L shell, in this atom, there are 8 electrons and it has reached its maximum capacity.
• The maximum no. of electrons that a shell can accommodate = 2n²; where n = shell number, in this case, n = 2.
• ∴ Max capacity = 2 × 4 = 8.

Therefore, the final answers are: 1.) Sodium

                                                         2.) 11 electrons

                                                         3.) L shell

                                                         4.) 8 electrons

For a similar question on atoms, refer to:

https://brainly.in/question/47639904

#SPJ2