Observe the following figure:
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Solution....
1. In ∆ABC & ∆DBC
=>BC=BC (Common)
=> ang. ABC = ang. DBC { GIVEN IN FIGURE}
=> ang.ACB = ang.DBC { GIVEN IN FIGURE}
.
. . ∆ABC is congruent to ∆DBC by ASA criteria (ANGLE SIDE ANGLE )
2. YES , BOTH THE TRIANGLES ARE CONGRUENT TO EACH OTHER ,, HENCE WE PROVED IN FIRST QUESTIONS.
3. AB = DC (CPCT)
4. AC = DB {CPCT}
HENCE ,, I ANSWERED ALL ...
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