Question

Observe the following sets of quantum numbers for a
given orbital.
n = 4,1 = 2, m = 0
The correct orbital is
.​

Answer 1

Answer:

For L -

s - 0 , p - 1 , d - 2 , f - 3

Explanation:

so here L= 2

The orbital is 4d

Answer 2

The correct orbital is $d_{z^2}$.

• n is called the principal quantum number.
• l is called azimuthal quantum number. For l=2 the orbital is d.
• Thus for n=4 and l=2, the orbital is 4d.
• m is called magnetic quantum number. For m=0 the orbital is $d_{z^2}$.
• So, the correct orbital for the above sets of quantum numbers is $d_{z^2}$.