obtain a relation for distance traveled by any object moving with uniform acceleration between nth and (n + 1)th second
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1
Explanation:
From second equation of motion, s=ut+
2
1
at
2
The displacement after t = 5 seconds will be s
5
=5u+
2
1
a5
2
The displacement after t = 4 seconds will be s
4
=4u+
2
1
a4
2
Displacement between 4th and 5th second will be s
5
−s
4
=(5u+
2
1
a5
2
)−(4u+
2
1
a4
2
).
=u+
2
1
a(25−16)=u+
2
9
a
=
2
9
a
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