Obtain a relation for the distance traveled by an object moving with a uniform acceleration in the interval between 4and5 second.
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Answer:
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Explanation:
Correct option is
A
2
9
×acceleration
From second equation of motion, s=ut+
2
1
at
2
The displacement after t = 5 seconds will be s
5
=5u+
2
1
a5
2
The displacement after t = 4 seconds will be s
4
=4u+
2
1
a4
2
Displacement between 4th and 5th second will be s
5
−s
4
=(5u+
2
1
a5
2
)−(4u+
2
1
a4
2
).
=u+
2
1
a(25−16)=u+
2
9
a
=
2
9
a
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