Obtain all other zeros of polynomial x4 – 3√2x3 + 3 x2 + 3√2x – 4, if two of its zeros are √2 and 2√2.
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I didn't learn polynomial.
Step-by-step explanation:
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Answered by
1
Answer:
✿Yøur
-1
Solution :- given
⇒P(x)=x4−32x3+3x2+32x−4=0
as Two zero is given 2,22
∴(x−2)(x−22)=x2−32x+4
Now considering a standard quadratic equation
ax2+bx+c=0
We can say
(x2−32x+4)(ax2+bx+c)=p(x)
⇒ax4−3a2x3+4ax2+bx3−3b2x2+4bx+cx2−3c2x+4c=p(x)
⇒ax4
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