Question

obtain all the zeroes of the polynomial 9xto the power of 4-6xcube-35xsquare+24x-4 , if two zeroes are 2 and -2
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Answer 1

Answer:

Step-by-step explanation:

factors: (x-2) and (x+2)

g(x)=(x-2)(x+2)=$x^{2} -4$

p(x)divided by g(x)=$\frac{9x^{4} -6x^{3}-35x^{2} +24x-4}{x^{2}-4} =$$9x^{2} -6x+1$

on factorizing $9x^{2} -6x+1, we get (3x-1)(3x-1)$

therefore zeroes are $\frac{1}{3} , \frac{1}{3}, 2 and -2$

make sure you write all 4 zeroes at the end even if two of them are same. Because $x^{4}$ indicates that no. of zeroes is 4.