Obtain all the zeroes of x^4-7x^3+17x^2-17x+6,if two of its zeroes are 3 and 1
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hey mate here is your answer...
given two zeroes if the polynomial therefore we can write.... (x-3)(x-1) =x^2 -4x+3
although we got this from it's zeroes it will be a perfect root of above polynomial... therefore by dividing we get === x^2-3x+2
by factorising this we can get the zeroes....that is.. 1,2,1,and 3
hope you like this... plz mark as brainliest
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