Obtain all zeroes of the polynomial x^4-x^3-7x^2+x+6 if two zeroes are 3 and 1
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f(×)=0=×4-×3-7×2+×+6=0
- f(3)=0
=(3)4-(3)3-7(3)2+3+6
=81-27-7(9)+3+6
=81-27-63+9
=90-90
=0
- f(1)=0
=(1)4-(1)3-7(1)2+1+6
=1-1-7+1+6
=-7+7-1+1
=0
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