Question

Obtain all zeros of the polynomial (2x^3-4x-x^2+2).If two of the zeros are√2&-√2.

Answer 1

Hello friends!!

Here is your answer :

P(x) = 2x³ - 4x - x² + 2

Two of the Zeroes of p (x) =
$\sqrt{2} \: \: and \: \: - \sqrt{2}$



Let the other zero be x

$product \: \: of \: \: zeroes \: = \frac{constant \: \: term \: }{coefficient \: \: of \: \: {x}^{3} }$



$( \sqrt{2} )( - \sqrt{2} )(x) = \frac{2}{2}$


$- 2x = 1$

$x = \frac{ - 1}{2}$


Therefore,

All the Zeroes are

$\sqrt{2} \: \: \: ,\: \: \: - \sqrt{2} \: \: \: , \: \: \frac{ - 1}{2}$


Hope it helps you...

#Be Brainly

Answer 2

Here is your answer :

P(x) = 2x³ - 4x - x² + 2

Two of the Zeroes of p (x) =
\sqrt{2} \: \: and \: \: - \sqrt{2}



Let the other zero be x

product \: \: of \: \: zeroes \: = \frac{constant \: \: term \: }{coefficient \: \: of \: \: {x}^{3} }



( \sqrt{2} )( - \sqrt{2} )(x) = \frac{2}{2}


- 2x = 1

x = \frac{ - 1}{2}


Therefore,

All the Zeroes are

\sqrt{2} \: \: \: ,\: \: \: - \sqrt{2} \: \: \: , \: \: \frac{ - 1}{2}
Hope it was helpful