Question

Obtain all zeros of x4 - 7x3 - 17 x +6 if 2 zeros are 3 and 1

Answer 1

I think something is wrong here.

Answer 2

Answer:

let p(x)=p(3),

p(x)=p(1)

Step-by-step explanation:

(i) p(x)=x4-7x3-17 x +6

p(3)=(3)4-7(3)3-17(3)+6

=12-63-51+6

p(3)=-96

(ii) p(x)=x4-7x3-17 x +6

p(1)=(1)4-7(1)3-17(1)+6

=4-21-17+6

p(1)=-172