obtain an expression for the angle of lean when a cyclist takes a curved path
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Mass of cyclist + cycle = M
Radius of curvature of the curved path = R
Angle of inclination from vertical = Ф
Acceleration due to gravity = g
Velocity of the cyclist = v
Let the normal force : N from the ground into the cyclist. Balance force is in horizontal and vertical directions.
N sin Ф = M v² / R = centripetal force for the cyclist to move in a curve of radius R
N cos Ф = M g = weight balanced by normal reaction from ground
So, by dividing equation 1 by 2
Tan Ф = v² / Rg
Ф = tan⁻¹ (v² / R g)
Radius of curvature of the curved path = R
Angle of inclination from vertical = Ф
Acceleration due to gravity = g
Velocity of the cyclist = v
Let the normal force : N from the ground into the cyclist. Balance force is in horizontal and vertical directions.
N sin Ф = M v² / R = centripetal force for the cyclist to move in a curve of radius R
N cos Ф = M g = weight balanced by normal reaction from ground
So, by dividing equation 1 by 2
Tan Ф = v² / Rg
Ф = tan⁻¹ (v² / R g)
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2
Answer:
andy7 Ace
speed = total distance / total time taken
8 km/hr = 21000/t (as distance is given in meter we have to change in kilometer so, 21m = 0.021km
t = 0.021/8
t = 0.02625 hrxplanation:
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