Science, asked by shreshthi9743, 1 year ago

Obtain an expression for the heat produced in a conductor when a voltage v is applied across it. heating effect of electric current is desirable as well as undesirable. explain this statement.

Answers

Answered by anushasahu
52

HEY MATE HERE IS YOUR ANSWER

To calculate the heat produced in a conductor, consider current I is flowing through a conductor AB of resistance R for time t. also consider that the potential difference applied across its two ends is V.

Now, total amount of work done in moving a charge q from point A to B is given by:

W     =     q     X     V  ---- (1)

Now, we know that charge = current × time

or        q     =     I     X     t

and      V     =     I     X     R (Ohm’s law)

Putting the values of q and V in equation (1), we get

W     =     (I   X   t)    X    (I   X   R)

Or    

W     =     I^2Rt

Now, assuming that all the work done is converted into heat energy we can replace symbol of ‘work done’ with that of ‘heat produced’. So,

H     =     I^2RT

HOPE THIS HELPS YOU...

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Answered by sourasghotekar123
0

Answer:

Explanation:

    According to ohms law V=IR-------(1)

               Current flowing   =I=\frac{Q}{T}

                                           Q=I*T--------(2)

       From potential difference formula(V)=W/Q

                        Work done(W)=   V*Q-------(3)

                   From equation (1) and (2)and subtuting in equation(3)

                     work done=   (I*R)*(I*T)

                                        =I^{2} *R*T

                        Heat energy is northing but work done by the conductor.

                                      H=I^{2} *R*T

                                       H=\frac{V^{2} }{R} *T              (I=V/R)

                                       H=PT                   (P=V^{2} /R)

         Heating effect is desirable because it is useful for the functioning of electrical bulbs, and undesirable because it leads to unnecessary loss of energy.                

  The project code is #SPJ2          

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