Question

Obtain an expression for the time of flight of a projectile.
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Answer 1

Answer:

The amount of time it spends in the air is called the time of flight. If the ground from which the projectile is launched is level, the time of flight only depends on the initial velocity v0, the launch angle θ, and the acceleration due to gravity. The unit for the time of flight is seconds (s).

Answer 2

Answer:

distance: thetha =12sin-1 (gdv 2)thetha=1 2 sin-1 (gdv 2)

Explanation:

the time of the flight of an object,given the initial launch angle and initial velocity is found with:T=2v sin thetha g,T=2vi sin.The angle of reach is the angle the object must be launched at in order to achieve specific distance: thetha=12sin-1 (gdv 2 ) thetha=1 2 sin-1 (gdv2)