Question

obtain derivatives x sin x​

Answer 1

Answer :

Let, y = x sinx .....(i)

We use the rule -

d/dx (uv) = u dv/dx + v du/dx ,

where u, v are functions of x

Differentiating both sides of (i) with respect to x, we get

dy/dx = d/dx (x sinx)

= x d/dx (sinx) + sinx d/dx (x)

= x (cosx) + sinx (1)

= x cosx + sinx

Therefore, the required derivative is

x cosx + sinx.