Question

Obtain equation of motion for a body projected vertically upward using the equations of uniform accelerated motion

Answer 1

$v=u-gt$

$s=ut-\frac{1}{2}gt^2$

$v^2=u^2-2gh$

Explanation

Let the the body is projected with initial velocity u and after time t its velocity is v and and in time t it will cover a height of h

Acceleration due to gravity is $g=9.8m/sec^2$

Now first equation of motion

$v=u+gt$, here body is projected upward so g = -g

So $v=u-gt$

Second equation of motion is $s=ut+\frac{1}{2}gt^2$

For upward motion $s=ut-\frac{1}{2}gt^2$

Third equation of motion is $v^2=u^2+2gh$

For upward motion

$v^2=u^2-2gh$

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Answer 2

Explanation:

all are upwards