Question

Obtain expressions for the work done, change in internal energy and heat supplied in an isobaric process on a gas

Answer 1

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★TO FIND:-

An expression for work done, change in internal energy and heat supplied in an isobaric process on a gas

★SOLUTION:-

Isobaric process means a thermidynamic process associated with constant external pressure

Let,

• Internal energy change = ∆U

• Number of moles = μ

• Work = W

• Heat change = ∆Q

In Constant Pressure, the heat change is :-

$: \longrightarrow \displaystyle \sf{∆Q = \mu C_p\triangle\theta \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (1)}$

In all thermodynamics process, ∆U is given as :-

$: \longrightarrow \displaystyle \sf{∆U = \mu C_v \triangle\theta \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (2)}$

As according to first law of thermodynamics:-

$\displaystyle \sf{ \therefore∆Q = ∆U + W} \\ \\ \rightarrow \displaystyle \sf{ \mu C_p \triangle\theta = \mu \: C_v \triangle \theta + W} \\ \\ { \boxed{ \sf{W = \mu \: (C_v - C_p) \triangle \: \theta}}}$

It can also be represented by:-

$\rightarrow \displaystyle{ \boxed{ \sf{ \pink{W = P∆V}}}}$

Answer 2

W = P∆V

Hope it helps:)✿✿✿✿✿