Question

obtain
field
a relation blw electric
intensity and potential difference​

Answer 1

Answer:

Electric field intensity is equal to the negative of rate of change of potential with respect to the distance or it can be defined as the negative of the rate of derivative of potential difference, V with respect to r,E=-dV/dr.

Answer 2

Answer:

The relation is very simple. Electric field intensity is equal to the negative of rate of change of potential with respet to the distance or it can be defined as the negative of the rate of derivative of potential difference, V with respect to r, E = - dV/dr.

Explanation:

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