Physics, asked by whusnasweety07, 9 hours ago

obtain the expression for self induction of a long solenoid​

Answers

Answered by iAmHoBiSpRiTexD
2

Answer:

So the expression for the coefficient of self-inductance is μ0n2Al. Note The flux through one solenoid coil is ϕ=B×A where the area of the cross section of each turn is A. For the n number of turns then the total magnetic flux is ϕ=n×B×A. The magnetic field is uniform inside the solution.

Answered by adityarajop56i40
0

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