Odds are 8: 5 against a man, who is 55 years old, living till he is 75 and 4 : 3 against his wife who is now 48, living till she is 68. Find the probability that (a) the couple will be alive 20 years hence (b) atlast one of them will be alive 20 years hence.
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Answer:
= 44/91
Step-by-step explanation:
The probability that the man will be alive in 20 years time = 5/13
The probability that the man will be dead in 20 years time = 8/13
The probability that the wife will be alive in 20 years time = 3/7
The probability that the woman will be dead in 20 years time = 4/7
the probability that either of them will be alive in 20 years time
= the probability that the man is a live and the woman is dead OR the man is dead and the woman is alive
= 5/13 x 4/7 + 8/13 x 3/7
= 20/91 + 24/91
= 44/91
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