Math, asked by satenderv410, 11 months ago

Odds are 8 to 5 against a person who is 40 years old living till he is 70 years and 4 to 3 against another person who is now 50 years old living till he is 80 years. Probability that one of then will be alive for next 30 years is:

Answers

Answered by aristeus
2

Probability will be \frac{15}{91}

Step-by-step explanation:

We have given that odds are 8 to 5 against a person he will alive more thirty years

So the probability that the man will be alive in next 30 years  = \frac{5}{13}

The probability that the man will be dead in next 30 years =  \frac{8}{13}

Now for second man there is 4 to against that he will alive next thirty years

So the probability that the other man will be alive in next 30 years = \frac{3}{7}

And The probability that the man will be dead in next 30 years =  \frac{4}{7}

the probability that both men are alive for 30 next years =  \frac{5}{13}\times \frac{3}{7}=\frac{15}{91}

Learn more

Odds are 8:5 against a man who is 55 years old, living till he is 75 and 4:3 against his wife who is now 48, leaving till she is 68. find the probability that one couple will be alive live 20 years hence

https://brainly.in/question/2613051

Similar questions