Math, asked by H4R5H, 1 year ago

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Answered by TPS
2
Subtracting -32/13 from -6/5

 \frac{ - 6}{5} - \bigg( \frac{ - 32}{13} \bigg) \\ \\ = \frac{ - 6}{5} + \frac{ 32}{13} \\ \\ lcm \: of \: 13 \: and \: 5 \: = 13 \times 5 = 65 \\ \\ = \frac{13 \times ( - 6) + 5 \times 32}{65} \\ \\ = \frac{ - 78 + 160}{65} \\ \\ = \frac{82}{65}
Answered by Anonymous
0

Answer:

 \Huge   \frac{82}{65}

Step-by-step explanation:

Subtracting -32/13 from -6/5

 \begin{lgathered}\frac{ - 6}{5} - \bigg( \frac{ - 32}{13} \bigg) \\ \\ = \frac{ - 6}{5} + \frac{ 32}{13} \\ \\ lcm \: of \: 13 \: and \: 5 \: = 13 \times 5 = 65 \\ \\ = \frac{13 \times ( - 6) + 5 \times 32}{65} \\ \\ = \frac{ - 78 + 160}{65} \\ \\ = \frac{82}{65}\end{lgathered}

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