Physics, asked by onzrockers, 5 months ago

of 12 km/hr and downhill on same incline at 16 km/hr. Air resistance is
proportional to square of his speed and his maximal effort which he
applies on pedal which causes friction on tyre to move the cycle is
independent of speed. His maximum speed on his maximal effort on a
flat road is close to :-
(A) 20 km/hr
(B) 18 km/hr
(C) 22 km/hr
(D) 14 km/hr

Answers

Answered by syedazainabrizvi
0

Explanation:

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Answered by milindtelgote27
1

Explanation:

Net acceleration is due to braking and centripetal acceleration

Due to Braking,

a

T

=0.5m/s

2

Speed of the cyclist, v=27km/h=7.5m/s

Radius of the circular turn, r=80m

Centripetal acceleration is given as:

a

c

=

r

V

2

=(7.5

2

)/80=0.70m/s

2

Since the angle between a

c

and a

T

is 900, the resultant acceleration a is given by:

a=(a

c

2

+a

T

2

)

1/2

a=(0.7

2

+0.5

2

)

1/2

=0.86m/s

2

tanθ=

a

T

a

c

where θ is the angle of the resultant with the direction of the velocity.

tanθ=

0.5

0.7

=1.4

θ=tan

−1

(1.4)=54.56

0

Answered By

toppr

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