Question

of 5 grams of sugar is dissolve in 100 cm³ of water is called: 1)%w/w 2)%w/v 3%v/v 4)v/w​

Answer 1

Answer:

$\large{\underline{\boxed{\sf 4.76 \: \%}}}$

Explanation:

Given that ;

Mass of sugar (solute) = 5g

Mass of water (solvent) = 100 g

Total mass of solution = Mass of solute + solvent

⇒ Total mass = (5 + 100)g

⇒ Total mass = 105 g

$\rule{300}{2}$

We know that,

$\rm Concentration \: \% = \dfrac{Mass \: of \: Solute}{Mass \: of \: Solution}Concentration%= </p><p>MassofSolution$

MassofSolute

⇒

$\rm Concentration \: \% = \dfrac{5}{105} * 100Concentration%$

=

105/5 ∗100

⇒

$\rm Concentration \: \% = \dfrac{100}{21}Concentration%= </p><p>21</p><p>100</p><p>$

⇒

$\rm Concentration \: \% = 4.76 \%Concentration%=4.76%$

Hence, the concentration is 4.76 %.