of a and b are rational number and 5+2underroot3 upon 7+4underoot 3=a-b underroot 3 find the value of a and b .
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Answer:
lhs = (5+2√3)/(7+4√3)
= [(5+2√3)(7-4√3)]/[(7-4√3)(7+4√3)]
=[35-20√3+14√3-24]/[7²-(4√3)²]
=[11-6√3]/[49-48]
=11-6√3
therefore
11-6√3 = a+b√3
compare both sides
a = 11, b = -6
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