Question

of a+b= x²,a-b= x-m and x id not equal to 0 then (a+b) (a-b)​

Answer 1

Answer:

1

Step-by-step explanation:

If

${(a + b)} = {x}^{ m} \: \: {(a + b)} = {x}^{ - m}$

Then (a + b) ( a - b)

${x}^{m} \times {x}^{ - m}$

${x}^{ m + ( - m)}$

${x}^{0}$

$1$