Physics, asked by tsrandcompany, 7 months ago

of a rope
15. A block of mass 'M' is lowered with the help
of negligible mass through a distance
'd' with an acceleration of
g
Work done by
3
rope on the block is
the
ad​

Answers

Answered by patelharshad9082
0

Answer:

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Explanation:

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Answered by TheUnsungWarrior
0

Answer:

The work done by the rope on the block is - 2 Mg d/3.

Explanation:

Given: Mass = M

  displacement = d

  downward acceleration g/3.

To find: Work done by the rope.

Solution: Through the concept of #Pseudo Force, we know that:

              Tension, T = m (g-a)

For the above case:

                    T = M ( g - g /3)

                   T = 2 Mg/3

#For work done, we know that:

                   W = F s cos∅

                   W = 2 Mg/3 × d × cos 180°

[∵ T = F = 2 Mg/3 and ∅ = 180° for the rope is descending straightly]

                   W = - 2 Mg d/3

Hence, the work done by the rope on the block is - 2 Mg d/3.

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