of a rope
15. A block of mass 'M' is lowered with the help
of negligible mass through a distance
'd' with an acceleration of
g
Work done by
3
rope on the block is
the
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Answer:
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Explanation:
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Answered by
0
Answer:
The work done by the rope on the block is - 2 Mg d/3.
Explanation:
Given: Mass = M
displacement = d
downward acceleration g/3.
To find: Work done by the rope.
Solution: Through the concept of #Pseudo Force, we know that:
Tension, T = m (g-a)
For the above case:
T = M ( g - g /3)
T = 2 Mg/3
#For work done, we know that:
W = F s cos∅
W = 2 Mg/3 × d × cos 180°
[∵ T = F = 2 Mg/3 and ∅ = 180° for the rope is descending straightly]
W = - 2 Mg d/3
Hence, the work done by the rope on the block is - 2 Mg d/3.
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