Question

of ax^2+bx+c is excatly divisible by (x-1)(x-2) and leaves remainder is 0 and dividend is x+1 then the remainder is 6.find a,b,c​

Answer 1

Answer:

(x-1)(x-2)

=x^2-x-2x+2

=x^2-3x+2

compair with the equation ax^2+bx+c

we get,

a=1 , b= -3 , c= 2

if we divide the equation x^2-3x+2 by x+1

x+1 | x^2-3x+2 | x -4

x^2+x

-

-4x+2

-4x-4

+. +

+6

si the remainder is 6

so, a=1 , b= -3 , c =2