Math, asked by soulakhil494, 9 months ago

Of one of the Zeroes of polynomial p (x)= (k-1) x²-kx +1 is ​

Answers

Answered by MaheswariS
1

\underline{\textbf{Given:}}

\textsf{Polynomial is}

\mathsf{P(x)=(k-1)x^2-kx+1}

\underline{\textbf{To find:}}

\textsf{One of the zeroes of P(x)}

\underline{\textbf{Solution:}}

\mathsf{Consider,}

\mathsf{P(x)=(k-1)x^2-kx+1}

\mathsf{Sum\;of\;the\;coefficients}

\mathsf{=(k-1)-k+1}

\mathsf{=0}

\therefore\mathsf{x-1\;is\;a\;zero\;of\;P(x)}

\underline{\textbf{Find more:}}

If p(x) =x²-3x+5then the value of p (-2)is​

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