Question

of system of equations 4x+6y = 21 and px- 2y = 15
has unique solutions determine
p.​

Answer 1

Ans) ⇒ p ≠ √(-8)

Step-by-step explanation:

Given:

The system of equations: 4x+py=21 and px-2y=15

To find:

If the system of equations: 4x+py=21 and px-2y=15 has unique solutions , then which of the following could be the value of p?

Solution:

Condition for the system of equations a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0  to have unique solution is,

a1/a2 ≠ b1/b2

From given, we have,

4x + py = 21 and px - 2y = 15

a1 = 4 and a2 = p

b1 = p and b2 = -2

c1 = 21 and c2 = 15

4/p ≠ p/-2

⇒ p × p ≠ 4 × -2

⇒ p² ≠ -8

⇒ p ≠ √(-8)

Therefore, for all the values other than √(-8), the system of equations will have unique solution.

Follow me

mark me as briliant

:)

Answer 2

Answer:

-4/3 is the correct answer