Math, asked by sreyamarium5796, 1 year ago

Of the 3 numbers the first and second are in the ratio of 5:2 and the first and the third are in the ratio of 3:4 the average is 123

Answers

Answered by MarvelEdge17
0

Answer:

135 ; 54 ; 180

Step-by-step explanation:

Let the 1st number be a ; 2nd be b and the 3rd be c.

1st : 2nd number = a/b=5/2 ; 2a = 5b ; b = 2a/5

1st : 3rd number = a/c = 3/4 ; 4a = 3c ; c = 4a/3

As the average is 123; (a+b+c)/3 = 123

Replacing values of b and c we get;

(a + 2a/5 + 4a/3)/3 = 123

(15a+6a+20a)/15 = 3*123

41a/15 = 369

41a = 5535

a = 5535/41 = 135

b = 2*135/5 = 54

c = 4*135/3 = 180

Similar questions