Question

of the diagonals AC and BD of a rhombus ABCD meet at O. If AC = 8 cm and
BD = 6 cm, find sin ∆OCD.​

Answer 1

Sin∠OCD  = 3/5  if diagonals AC and BD of a rhombus ABCD meet at O . AC = 8 cm & BD = 6 cm

Step-by-step explanation:

diagonals AC and BD of a rhombus ABCD meet at O

Diagonals of a Rhombus perpendicularlly bisect each other

=> AO  = OC  = AC/2  = 8/2 = 4 cm

Similalrly

BO  = OD  = BD/2  = 6/2   = 3 Cm

in Δ OCD

OC = 4 cm

OD = 3 cm

CD² = OC² + OD²

=> CD² = 4² + 3²

=> CD² = 25

=> CD = 5 cm

sin ∠OCD  = OD/CD

=> Sin∠OCD  = 3/5

Learn more

Show that the diagonals of a rhombus divide it into four congruent ...

https://brainly.in/question/11763339

The diagonals seg XZ and seg YW of the rhombus XYZW intersect at ...

https://brainly.in/question/11762624

Answer 2

Given: The diagonals $AC$ and $BD$ of a rhombus $ABCD$ meet at $O$ and $AC=8\ cm,BD=6\ cm$

To Find: $sin \angle OCD= ?$

Step-by-step explanation:

In the figure $AC=8\ cm,BD=6\ cm$

We know, Rhombus Diagonal bisect each other.

So, $AO=OC=4\ cm\ and\ Bo=OD=3\ cm$

∴ From $\triangle COD$,

⇒$sin \angle OCD=\frac{DO}{CD}$

⇒$sin \angle OCD=\frac{3}{5}$

Therefore, The Answer is $\frac{3}{5}$.