Math, asked by mamtachoudharyy30, 8 months ago

of the floor of a room is 12 metre long and 6 metre wide the floor of this room is to be fitted with tiles of dimension tense and X2 cm what will be the total expense in Rupees if the cost of tiling is ruppes 5 a tile​

Answers

Answered by topwriters
23

Cost of flooring the room is Rs. 1,80,000.

Step-by-step explanation:

Note: There is some typographical error in the question. Assuming that the dimension of the tile is 10 cm * 2 cm, please find solution below.

Given: Floor of a room is 12 metre long and 6 metre wide. To be fitted with tiles of dimension 10 cm * 2 cm. Cost of one tile is Rs. 5.

Find: Total expense of flooring the room.

Solution:

Area of room = length * breadth = 12 * 6 = 72 m² = 720000 cm²

Area of one tile = 10 * 2 = 20 cm²

Number of tiles required = 720000 / 20 = 36000

Price of one tile = Rs. 5

Total price of all tiles = 5 * 36000 = Rs. 1,80,000

Cost of flooring the room is Rs. 1,80,000.

If the dimension of tile is different, please re-calculate the cost using the same method as above.

Answered by mahik88377
6

floor of a room is 180000

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