Math, asked by meshramspandan3, 6 months ago

of the ratio of the height of the tower and the length of the shadow is √3:1 what is the angle of elevation of the sun

Answers

Answered by kondalaprasad88
0

Step-by-step explanation:

If the ratio of the height of a tower and the length of its shadow is √3 :1, then the angle of elevation of the Sun is 30º.

mark as brainlist answer please

Answered by MaIeficent
6

Step-by-step explanation:

Diagram:-

\setlength{\unitlength}{1cm}\begin{picture}(6,5)\linethickness{.4mm}\put(1,1){\line(1,0){4.5}}\put(1,1){\line(0,1){3.5}}\qbezier(1,4.5)(1,4.5)(5.5,1)\put(.3,2.5){\large\bf}\put(2.8,.3){\large\bf}\put(1.02,1.02){\framebox(0.3,0.3)}\put(.7,4.8){\large\bf A}\put(.8,.3){\large\bf B}\put(5.8,.3){\large\bf C}\qbezier(4.5,1)(4.3,1.25)(4.6,1.7)\put(3.8,1.3){\large\bf $\Theta$}\end{picture}

Given:-

  • The ratio of the height of the tower and length of the shadow is √3 : 1.

To Find:-

  • The angle of elevation of the sun.

Solution:-

Let AB be the height of the tower and

BC be the length of the shadow.

ATQ:-

Ratio of the height of tower and length of shadow is √3 : 1

\sf \dfrac{AB}{BC} = \dfrac{\sqrt{3}}{1}

In a right angled triangle.

\sf \dfrac{Opposite \: side}{Adjacent \: side} = tan\theta

So, In △ABC

\sf \dfrac{AB}{BC} = tan\theta

\sf \dfrac{AB}{BC} = tan\theta

\sf \implies \dfrac{ \sqrt{3} }{1} = tan\theta

\sf \implies \sqrt{3} = tan\theta

\sf \implies tan60 ^{ \circ}  = tan\theta

\sf \implies  \theta = 60 ^{ \circ}

\underline{\boxed{\therefore \sf Angle \: of \: elevation \: of \: the \: sun = 60 ^{ \circ} }}

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