Question

Mohit is twice as old as his brother Sanjay. If the difference of their ages be 9 years, find their present ages.​

Answer 1

Let Sanjay's age be x

Mohit's age = 2x

Difference = 9 years

Thus, 2x - x = 9 years

x = 9

Thus,

Sanjay's age = 9 years

Mohit's age = 9 × 2 = 18 years

$\mathfrak {Follow \ !!}$

Answer 2

Answer:

let Mohan's brother age be x

Mohan's age will be 2x

2x-x=9

2x-x=x

therefore,x=9